1/6x^2-81=0

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Solution for 1/6x^2-81=0 equation:



1/6x^2-81=0
Domain of the equation: 6x^2!=0
x^2!=0/6
x^2!=√0
x!=0
x∈R
We multiply all the terms by the denominator
-81*6x^2+1=0
Wy multiply elements
-486x^2+1=0
a = -486; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-486)·1
Δ = 1944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1944}=\sqrt{324*6}=\sqrt{324}*\sqrt{6}=18\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{6}}{2*-486}=\frac{0-18\sqrt{6}}{-972} =-\frac{18\sqrt{6}}{-972} =-\frac{\sqrt{6}}{-54} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{6}}{2*-486}=\frac{0+18\sqrt{6}}{-972} =\frac{18\sqrt{6}}{-972} =\frac{\sqrt{6}}{-54} $

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